Introduction
Introduction - "Practical Geometry" Chapter 14 - Class 6th Maths
Q 1 - Ex 14.1 - Practical Geometry - NCERT Maths Class 6th - Chapter 14
Page No 276:
Question 1:
Draw a circle of radius 3.2 cm.Answer:
The required circle can be drawn as follows.Step 1
First, open the compasses for the required radius 3.2 cm.
Step 2
Mark a point ‘O’ where we want the centre of the circle to be.
Step 3
Place the pointer of compasses on O.
Step 4
Turn the compasses slowly to draw the circle.
Q 2 - Ex 14.1 - Practical Geometry - NCERT Maths Class 6th - Chapter 14
Question 2:
With the same centre O, draw two circles of radii 4 cm and 2.5 cm.Answer:
The required circle can be drawn as follows.Step 1
First, open the compasses for the required radius 4 cm.
Step 2
Mark a point ‘O’ where we want the centre of the circle to be.
Step 3
Place the pointer of compasses on O.
Step 4
Turn the compasses slowly to draw the circle.
Step 5
Now, open the compasses for 2.5 cm.
Step 6
Again put the pointer of the compasses on point ‘O’ and turn the compasses slowly to draw the circle.
Q 3 - Ex 14.1 - Practical Geometry - NCERT Maths Class 6th - Chapter 14
Question 3:
Draw a circle and any two of its diameters. If you join the ends of these diameters, what is the figure obtained? What figure is obtained if the diameters are perpendicular to each other? How do you check your answer?Answer:
A circle can be drawn of any convenient radius, also having its centre as O. Let AB and CD be two diameters of this circle. When we join the ends of these diameters, a quadrilateral ACBD is formed.
As we know that the diameters of a circle are equal in length, therefore, the quadrilateral so formed will have its diagonals of equal length.
Also, OA = OB = OC = OD = radius r and if a quadrilateral has its diagonals of same length which are bisecting each other, then it will be a rectangle.
Let DE and FG be two diameters of this circle such that these are perpendicular to each other. A quadrilateral is formed by joining the ends of these diameters.
Here, OD = OE = OF = OG = radius r
In this quadrilateral DFEG, the diagonals are equal and perpendicular to each other. Also, since these are bisecting each other, it will be a square.
The length of the sides of the quadrilateral so formed can be measured to check our answers.
Q 4 - Ex 14.1 - Practical Geometry - NCERT Maths Class 6th - Chapter 14
Question 4:
Draw any circle and mark points A, B and C such that(a) A is on the circle. (b) B is in the interior of the circle.
(c) C is in the exterior of the circle.
Answer:
A circle and three required points A, B, C can be drawn as follows.
Q 5 - Ex 14.1 - Practical Geometry - NCERT Maths Class 6th - Chapter 14
Question 5:
Let A, B be the centres of two circles of equal radii; draw them so that each one of them passes through the centre of the other. Let them intersect at C and D.Examine whether
and 
are at right angles.Answer:
Let us draw two circles of same radius which are passing through the centres of the other circle.
Here, point A and B are the centres of these circles and these circles are intersecting each other at point C and D.
In quadrilateral ADBC,
AD = AC (Radius of circle centered at A)
BC = BD (Radius of circle centered at B)
As radius of both circles are equal, therefore, AD = AC = BC = BD
Hence,
is
a rhombus and in a rhombus, the diagonals bisect each other at 90°.
Hence, and are at right angles.
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