Friday, May 29, 2020

NCERT solution class 9 chapter 1 Number Systems exercise 1.3 mathematics

EXERCISE 1.3



EVIDYARTHI

Q 1 (i, ii, iii), Ex 1.3, Page No 14, Number Systems, Class 9 Maths Solutions

Q 1 (iv, v, vi), Ex 1.3, Page No 14, Number Systems, Class 9th Maths


MKR
Decimal Expansion of Real Numbers Class - 9th CBSE NCERT


Class - 9th, Ex - 1.3, Q 1 ( NUMBER SYSTEM ) CBSE NCERT

Page No 14:

Question 1:

Write the following in decimal form and say what kind of decimal expansion each has:
(i) $\frac{36}{100}$

(ii) $\frac{1}{11}$

(iii) $4 \frac{1}{8}$

(iv) $\frac{3}{13}$

(v) $\frac{2}{11}$

(vi) $\frac{329}{400}$

Answer:

(i) $\frac{36}{100}=0.36$
Terminating

(ii) $\frac{1}{11}=0.090909 \ldots \ldots=0 . \overline{09}$
Non-terminating repeating

(iii) $4 \frac{1}{8}=\frac{33}{8}=4.125$
Terminating

(iv) $\frac{3}{13}=0.230769230769 \ldots=0 . \overline{230769}$
Non-terminating repeating

(v) $\frac{2}{11}=0.18181818 \ldots \ldots .=0 . \overline{18}$
Non-terminating repeating

(vi) $\frac{329}{400}=0.8225$
Terminating




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Q 2, Ex 1.3, Page No 14, Number Systems, CBSE Maths Class 9th



MKR

Class - 9th, Ex - 1.3, Q 2 ( NUMBER SYSTEM ) CBSE NCERT

Question 2:

You know that $\frac{1}{7}=0 . \overline{142857}$.
Can you predict what the decimal expansion of  $\frac{2}{7}, \frac{3}{7}, \frac{4}{7}, \frac{5}{7}, \frac{6}{7}$ are, without actually doing the long division? If so, how?

[Hint: Study the remainders while finding the value of  $\frac{1}{7}$ carefully.]

Answer:

Yes. It can be done as follows.

$\frac{2}{7}=2 \times \frac{1}{7}$ $=2 \times 0 . \overline{142857}=0 . \overline{285714}$

$\frac{3}{7}=3 \times \frac{1}{7}$ $=3 \times 0 . \overline{142857}=0 . \overline{428571}$

$\frac{4}{7}=4 \times \frac{1}{7}$ $=4 \times 0 . \overline{142857}=0 . \overline{571428}$

$\frac{5}{7}=5 \times \frac{1}{7}$ $=5 \times 0 . \overline{142857}=0 . \overline{714285}$

$\frac{6}{7}=6 \times \frac{1}{7}$ $=6 \times 0 . \overline{142857}=0 . \overline{857142}$



EVIDYARTHI

Q 3, Ex 1.3, Page No 14, Number Systems, Class 9th Maths



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Class - 9th, Ex - 1.3, Q 3 ( NUMBER SYSTEM ) CBSE NCERT

Question 3:

Express the following in the form $\frac{p}{q}$, where p and q are integers and q ≠ 0.
(i) $0 . \overline{6}$
(ii) $0.4 \overline{7}$
(iii) $0 . \overline{001}$

Answer:

(i) $0 . \overline{6}=0.666 \ldots$
Let x = 0.666…
10x = 6.666…
10= 6 + x
9x = 6
$x=\frac{2}{3}$


(ii) $0 . \overline{47}=0.4777 \ldots$

$=\frac{4}{10}+\frac{0.777}{10}$

Let x = 0.777…
10x = 7.777…
10= 7 + x
$x=\frac{7}{9}$

$\frac{4}{10}+\frac{0.777 \ldots}{10}=\frac{4}{10}+\frac{7}{90}$

$=\frac{36+7}{90}=\frac{43}{90}$

(iii) $0 . \overline{001}=0.001001 \ldots$
Let x = 0.001001…
1000x = 1.001001…
1000x = 1 + x
999x = 1
$x=\frac{1}{999}$


EVIDYARTHI

Q 4, Ex 1.3, Page No 14, Number Systems, Maths CBSE Class 9th R D Sharma Solutions



MKR

Class - 9th, Ex - 1.3, Q 4 ( NUMBER SYSTEM ) CBSE NCERT
Question 4:

Express 0.99999…in the form $\frac{p}{q}$. Are you surprised by your answer? With your teacher and classmates discuss why the answer makes sense.

Answer:

Let x = 0.9999…
10x = 9.9999…
10x = 9 + x
9x = 9
x = 1

EVIDYARTHI

Q 5, Ex 1.3, Page No 14, Number Systems, Mathematics Class 9th

MKRClass - 9th, Ex - 1.3, Q 5 ( NUMBER SYSTEM ) CBSE NCERT

Question 5:

What can the maximum number of digits be in the repeating block of digits in the decimal expansion of $\frac{1}{17}$? Perform the division to check your answer.

Answer:

It can be observed that,
$\frac{1}{17}=0 . \overline{0588235294117647}$
There are 16 digits in the repeating block of the decimal expansion of $\frac{1}{17}$


MKR

Class - 9th, Ex - 1.3, Q 6 ( NUMBER SYSTEM ) CBSE NCERT

Question 6:

Look at several examples of rational numbers in the form $\frac{p}{q}$(q ≠ 0), where p and q are integers with no common factors other than 1 and having terminating decimal representations (expansions). Can you guess what property q must satisfy?

Answer:

Terminating decimal expansion will occur when denominator q of rational number $\frac{p}{q}$ is either of 2, 4, 5, 8, 10, and so on…

$\frac{9}{4}=2.25$

$\frac{11}{8}=1.375$

$\frac{27}{5}=5.4$

It can be observed that terminating decimal may be obtained in the situation where prime factorisation of the denominator of the given fractions has the power of 2 only or 5 only or both.

EVIDYARTHI

Q 7, Ex 1.3,Page No 14, Number Systems, Class 9th Maths Solutions



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Class - 9th, Ex - 1.3, Q 7 ( NUMBER SYSTEM ) CBSE NCERT

Question 7:

Write three numbers whose decimal expansions are non-terminating non-recurring.

Answer:

3 numbers whose decimal expansions are non-terminating non-recurring are as follows.
0.505005000500005000005…
0.7207200720007200007200000…
0.080080008000080000080000008…


EVIDYARTHI

Q 8, Ex 1.3, Page No 14, Number Systems, CBSE Class 9th Maths



MKR

Class - 9th, Ex - 1.3, Q 8 ( NUMBER SYSTEM ) CBSE NCERT

Question 8:

Find three different irrational numbers between the rational numbers $\frac{5}{7}$ and $\frac{9}{11}$

Answer:

$\frac{5}{7}=0 . \overline{714285}$

$\frac{9}{11}=0 . \overline{81}$

3 irrational numbers are as follows.
0.73073007300073000073…
0.75075007500075000075…
0.79079007900079000079…




EVIDYARTHI
Q 9, Ex 1.3, Page No 14, Number Systems, Class 9th CBSE Maths


Question 9:

Classify the following numbers as rational or irrational:
(i) $\sqrt{23}$
(ii) $\sqrt{225}$
(iii) 0.3796
(iv) 7.478478
(v) 1.101001000100001…

Answer:

(i) $\sqrt{23}=4.79583152331 \ldots$
As the decimal expansion of this number is non-terminating non-recurring, therefore, it is an irrational number.

(ii) $\sqrt{225}=15=\frac{15}{1}$
It is a rational number as it can be represented in $\frac{p}{q}$ form.

(iii) 0.3796
As the decimal expansion of this number is terminating, therefore, it is a rational number.

(iv) 7.478478 …$=7 . \overline{478}$
As the decimal expansion of this number is non-terminating recurring, therefore, it is a rational number.

(v) 1.10100100010000 …
As the decimal expansion of this number is non-terminating non-repeating, therefore, it is an irrational number.

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