NCERT solution class 6 mathematics Chapter 1 Knowing Our Numbers Exercise 1.2

Exercise 1.2

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Ex-1.1
Ex-1.2
Ex-1.3

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Q 1 - Ex 1.2 - Knowing Our Numbers - Chapter 1 - Class 6th NCERT Maths

Page No 16:

Question 1:

A book exhibition was held for four days in a school. The number of tickets sold at the counter on the first, second, third, and final day was respectively 1094, 1812, 2050, and 2751. Find the total number of tickets sold on all the four days.

Answer:

Tickets sold on 1^st day = 1094
Tickets sold on 2^nd day = 1812
Tickets sold on 3^rd day = 2050
Tickets sold on 4^th day = 2751
Total tickets sold = 1094 + 1812 + 2050 + 2751
$\begin{array}{r}
1094 \\
1812 \\
2050 \\
+2751 \\
\hline 7707 \\
\hline
\end{array}$
∴ Total tickets sold = 7,707

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Q 2 - Ex 1.2 - Knowing Our Numbers - Chapter 1 - Class 6th NCERT Maths

Question 2:

Shekhar is a famous cricket player. He has so far scored 6980 runs in test matches. He wishes to complete 10, 000 runs. How many more runs does he need?

Answer:

Runs scored so far = 6980
Runs Shekhar wants to score = 10,000
More runs required = 10,000 − 6980
$\begin{array}{r}
10000 \\
-6980 \\
\hline 3020 \\
\hline
\end{array}$
∴ Shekhar requires 3,020 more runs.

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Q 3 - Ex 1.2 - Knowing Our Numbers - Chapter 1 - Class 6th NCERT Maths

Question 3:

In an election, the successful candidate registered 5, 77, 500 votes and his nearest rival secured 3, 48, 700 votes. By what margin did the successful candidate win the election?

Answer:

Votes secured by successful candidate = 5,77,500
Votes secured by rival = 3,48,700
Margin = 5,77,500 − 3,48,700
$\begin{array}{r}
577500 \\
-348700 \\
\hline 228800 \\
\hline
\end{array}$
∴ Margin = 2,28,800

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Q 4 - Ex 1.2 - Knowing Our Numbers - Chapter 1 - Class 6th NCERT Maths

Question 4:

Kirti bookstore sold books worth Rs 2,85,891 in the first week of June and books worth Rs 4,00,768 in the second week of the month. How much was the sale for the two weeks together? In which week was the sale greater and by how much?

Answer:

Value of Books sold in 1^st week = Rs 2,85,891
Value of books sold in 2^nd week = Rs 4,00,768
Total sale = Sale in 1^st week + Sale in 2^nd week
= 2,85,891 + 4,00,768
$\begin{array}{r}
285891 \\
+400768 \\
\hline 686659 \\
\hline
\end{array}$
The sale for the two weeks together was 6,86,659.
Since 4,00,768 > 2,85,891, sale in 2^nd week was greater than 1^st week.
$\begin{array}{r}
400768 \\
-285891 \\
\hline 114877 \\
\hline
\end{array}$
∴ The sale in 2^nd week was larger than the sale in 1^st week by Rs 1,14,877.

Page No 17:

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Q 5 - Ex 1.2 - Knowing Our Numbers - Chapter 1 - Class 6th NCERT Maths

 Question 5:

Find the difference between the greatest and the least number that can be written using the digits 6, 2, 7, 4, 3 each only once.

Answer 5:

Greatest number = 76432
Smallest number = 23467
Difference = 76432 − 23467
$\begin{array}{r}
76432 \\
-23467 \\
\hline 52965 \\
\hline
\end{array}$
Therefore, the difference between the greatest and the least number that can be written using the digits 6, 2, 7, 4, 3 each only once is 52,965.

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Q 6 - Ex 1.2 - Knowing Our Numbers - Chapter 1 - Class 6th NCERT Maths

 Question 6:

A machine, on an average, manufactures 2,825 screws a day. How many screws did it produce in the month of January 2006?

Answer 6:

Screws produced in one day = 2,825
Days in January = 31
Screws produced in 31 days = 2825 × 31
$\begin{array}{r}
\begin{array}{r}
2825 \\
\times 31 \\
\hline 2825
\end{array} \\
+84750 \\
\hline 87575 \\
\hline
\end{array}$
Therefore, screws produced during Jan, 06 = 87,575

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Q 7 - Ex 1.2 - Knowing Our Numbers - Chapter 1 - Class 6th NCERT Maths

Question 7:

A merchant had Rs 78,592 with her. She placed an order for purchasing 40 radio sets at Rs 1200 each. How much money will remain with her after the purchase?

Answer 7:

Cost of one radio set = Rs 1200
Cost of 40 radio sets = 1200 × 40 = Rs 48000
Money with Merchant = Rs 78,592
Money spent = Rs 48,000
Money left = 78592 − 48000
$\begin{array}{r}
78592 \\
-48000 \\
\hline 30592 \\
\hline
\end{array}$
Therefore, Rs 30,592 will remain with her after the purchase.

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Q 8 - Ex 1.2 - Knowing Our Numbers - Chapter 1 - Class 6th NCERT Maths

Question 8:

A student multiplied 7236 by 65 instead of multiplying by 56. By how much was his answer greater than the correct answer? (Hint: Do you need to do both the multiplications?)

Answer 8:

Difference between 65 and 56 = 9
Difference in the answer = 7236 × 9
$\begin{array}{r}
7236 \\
\times \quad 9 \\
\hline 65124 \\
\hline
\end{array}$
Therefore, his answer was greater than the correct answer by 65,124.

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Q 9 - Ex 1.2 - Knowing Our Numbers - Chapter 1 - Class 6th NCERT Maths

Question 9:

To stitch a shirt, 2m 15 cm cloth is needed. Out of 40 m cloth, how many shirts can be stitched and how much cloth will remain? (Hint: convert data in cm.)

Answer 9:

2 m 15 cm = 215 cm (1 m = 100 cm)
40 m = 40 × 100
= 4000 cm
Cloth required for one shirt = 215 cm
Number of shirts that can be stitched out of 4000 cm = 4000 ÷ 215

Therefore, 18 shirts can be made. 130 cm, i.e. 1 m 30 cm, cloth will remain.

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Q 10 - Ex 1.2 - Knowing Our Numbers - Chapter 1 - Class 6th NCERT Maths

Question 10:

Medicine is packed in boxes, each weighing 4 kg 500 g. How many such boxes can be loaded in a van which cannot carry beyond 800 kg?

Answer 10:

1 kg = 1000 g
4 kg 500 g = 4500 g
800 kg = 800 × 1000 = 800000 g
Number of boxes that can be loaded in the van = 800000 ÷ 4500

Hence, 177 boxes at maximum can be loaded in the van.

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Q 11 - Ex 1.2 - Knowing Our Numbers - Chapter 1 - Class 6th NCERT Maths

 Question 11:

The distance between the school and the house of a student’s house is 1 km 875 m. Everyday she walks both ways. Find the total distance covered by her in six days.

Answer 11:

Distance between school and house = 1 km 875 m
Now, 1 km = 1000 m
1 km 875 m = 1875 m
Distance covered each day = 1875 × 2 = 3750 m
Distance covered in 6 days = 3750 × 6
$\begin{array}{c}
3750 \\
\times 6 \\
\hline 22500 \\
\hline
\end{array}$
Therefore, distance covered in 6 days = 22,500 m
= 22.5 km or 22 km 500 m

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Q 12 - Ex 1.2 - Knowing Our Numbers - Chapter 1 - Class 6th NCERT Maths

Question 12:

A vessel has 4 litres and 500 ml of curd. In how many glasses, each of 25 ml capacity, can it be filled?

Answer 12:

Capacity of vessel = 4 l 500 ml
= 4500 ml (1 l = 1000 ml)
Capacity of a glass = 25 ml
Number of glasses that can be filled = 4500 ÷ 25

∴ 180 glasses can be filled.