Introduction
"Understanding Elementary Shapes" Chapter 5 - Introduction - Class 6th Maths
Q 1 - Ex 5.1 - Understanding Elementary Shape - NCERT Maths Class 6th - Chapter 5
Page No 88:
Question 1:
What is the disadvantage in comparing line segments by mere observation?Answer:
By mere observation, we cannot be absolutely sure about the judgement. When we compare two line segments of almost same lengths, we cannot be sure about the line segment of greater length. Therefore, it is not an appropriate method to compare line segments having a slight difference between their lengths. This is the disadvantage in comparing line segments by mere observation.Question 2:
Why is it better to use a divider than a ruler, while measuring the length of a line segment?Answer:
It is better to use a divider than a ruler because while using a ruler, positioning error may occur due to the incorrect positioning of the eye.Question 3:
Draw any line segment, say
[Note: If A, B, C are any three points on a line such that AC + CB = AB, then we can be sure that C lies between A and B]
Answer:
It is given that point C is lying somewhere in between A and B. Therefore, all these points are lying on the same line segment
For example,


Hence, relation AB = AC + CB is verified.
Page No 89:
Question 4:
If A, B, C are three points on a line such that AB = 5 cm, BC = 3 cm and AC = 8 cm, which one of them lies between the other two?Answer:
Given that,AB = 5 cm
BC = 3 cm
AC = 8 cm
It can be observed that AC = AB + BC
Clearly, point B is lying between A and C.
Question 5:
Verify, whether D is the mid point of

Answer:
From the given figure, it can be observed that


Clearly, D is the mid-point of AG.
Question 6:
If B is the mid point of

Answer:

Since B is the mid-point of AC,
AB = BC (1)
Since C is the mid-point of BD,
BC = CD (2)
From equation (1) and (2), we may find that
AB = CD
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