Exercise 11.2
Q 1 - Ex 11.2 - Algebra - NCERT Maths Class 6th - Chapter 11
Page No 230:
Question 1:
The side of an equilateral triangle is shown by l. Express the perimeter of the equilateral triangle using l.Answer:
Side of equilateral triangle = lPerimeter = l + l + l = 3l
Question 2:
(Hint: A regular hexagon has all its six sides equal in length.)
Answer:
Side of regular hexagon = lPerimeter = 6l
Q 3 - Ex 11.2 - Algebra - NCERT Maths Class 6th - Chapter 11
Question 3:
A cube is a three-dimensional figure as shown in the given figure. It has six faces and all of them are identical squares. The length of an edge of the cube is given by l. Find the formula for the total length of the edges of a cube.
Answer:
Length of edge = lNumber of edges = 12
Total length of the edges = Number of edges × Length of one edge
= 12l
Page No 231:
Question 4:
The diameter of a circle is a line which joins two points on the circle and also passed through the centre of the circle. (In the adjoining figure AB is a diameter of the circle; C is its centre.) Express the diameter of the circle (d) in terms of its radius(r).
Answer:
Diameter = AB = AC + CB = r + r = 2rd = 2r
Q 5 - Ex 11.2 - Algebra - NCERT Maths Class 6th - Chapter 11
Question 5:
To find sum of three numbers 14, 27 and 13, we can have two ways:(a) We may first add 14 and 27 to get 41 and then add 13 to it to get the total sum 54 or
(b) We may add 27 and 13 to get 40 and then add 14 to get the sum 54. Thus, (14 + 27) + 13 = 14 + (27 + 13)
This can be done for any three numbers. This property is known as the associativity of addition of numbers. Express this property which we have already studied in the chapter on whole numbers, in a general way, by using variables a, b and c.
Answer:
For any three whole numbers a, b, and c,(a + b) + c = a + (b + c)
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