NCERT solution class 8 chapter 10 Visualising Solid Shapes exercise 10.3

Exercise 10.3

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Question 1
Can a polyhedron have for its faces
(i) 3 triangles? (ii) 4 triangles?
(iii) a square and four triangles?
Sol :
(i) No, such a polyhedron is not possible. A polyhedron has minimum 4 faces.
(ii) Yes, a triangular pyramid has 4 triangular faces.

(iii) Yes, a square pyramid has a square face and 4 triangular faces.



Question 2
Is it possible to have a polyhedron with any given number of faces? (Hint: Think of a pyramid).
Sol :
A polyhedron has a minimum of 4 faces.

Q 3 - Ex 10.3 - Visualizing Solid Shapes - NCERT Maths Class 8th - Chapter 10

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Question 3
Which are prisms among the following?

(i)	(ii)
(iii)	(iv)

Sol :

(i) It is not a polyhedron as it has a curved surface. Therefore, it will not be a prism also.
(ii) It is a prism.
(iii) It is not a prism. It is a pyramid.
(iv) It is a prism.


Question 4
(i) How are prisms and cylinders alike?
(ii) How are pyramids and cones alike?
Sol :
(i) A cylinder can be thought of as a circular prism i.e., a prism that has a circle as its base.
(ii) A cone can be thought of as a circular pyramid i.e., a pyramid that has a circle as its base.

Question 5
Is a square prism same as a cube? Explain.
Sol :
A square prism has a square as its base. However, its height is not necessarily same as the side of the square. Thus, a square prism can also be a cuboid.

Q 6 - Ex 10.3 - Visualizing Solid Shapes - NCERT Maths Class 8th - Chapter 10

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Question 6
Verify Euler’s formula for these solids.

(i)	(ii)

Sol :

(i) Number of faces = F = 7
Number of vertices = V = 10
Number of edges = E = 15
We have, F + V − E = 7 + 10 − 15 = 17 − 15 = 2
Hence, Euler’s formula is verified.

(ii) Number of faces = F = 9
Number of vertices = V = 9
Number of edges = E = 16
F + V − E = 9 + 9 − 16 = 18 − 16 = 2
Hence, Euler’s formula is verified.

Q 7 - Ex 10.3 - Visualizing Solid Shapes - NCERT Maths Class 8th - Chapter 10

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Question 7
Using Euler’s formula, find the unknown.

Faces	?	5	20
Vertices	6	?	12
Edges	12	9	?

Sol :

By Euler’s formula, we have
F + V − E = 2
(i) F + 6 − 12 = 2
F − 6 = 2
F = 8
(ii) 5 + V − 9 = 2
V − 4 = 2
V = 6
(iii) 20 + 12 − E = 2
32 − E = 2
E = 30
Thus, the table can be completed as

Faces	8	5	20
Vertices	6	6	12
Edges	12	9	30

Q 8 - Ex 10.3 - Visualizing Solid Shapes - NCERT Maths Class 8th - Chapter 10

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Question 8
Can a polyhedron have 10 faces, 20 edges and 15 vertices?
Sol :
Number of faces = F = 10
Number of edges = E = 20
Number of vertices = V = 15
Any polyhedron satisfies Euler’s Formula, according to which, F + V − E = 2
For the given polygon,
F + V − E = 10 + 15 − 20 = 25 − 20 = 5 ≠ 2
Since Euler’s formula is not satisfied, such a polyhedron is not possible.