Tuesday, May 26, 2020

NCERT Solution class 7 chapter 2 exercise 2.7

Exercise 2.7



Q 1, Ex 2.7 - Fractions and Decimals - Chapter 2 - Maths Class 7th - NCERT

Question 1
Find:
(i) $0.4 \div 2$
Sol :
$0.4 \div 2$ $=\dfrac{4}{10} \div 2$

(ii) $0.35 \div 5$
Sol :
$0.35 \div 5$ $=\dfrac{35}{100} \div 5$ $=\dfrac{35}{100} \times \dfrac{1}{5}$ $=\dfrac{7}{100}$ = 0.07

(iii) $2.48 \div 4$
Sol :
$2.48 \div 4$ $=\dfrac{248}{100} \div 4$ $=\dfrac{248}{100} \times \dfrac{1}{4}$ $=\dfrac{62}{100}$ = 0.62

(iv) $65.4 \div 6$
Sol :
$65.4 \div 6$ $=\dfrac{654}{10} \div 6$ $\dfrac{654}{10} \times \dfrac{1}{6}$ $=\dfrac{109}{10}$ = 10.9

(v) $651.2 \div 4$
Sol :
$651.2 \div 4$ $=\dfrac{6512}{10} \div 4$ $=\dfrac{6512}{10} \times \dfrac{1}{4}$ $=\dfrac{1628}{10}$ = 162.8

(vi) $14.49 \div 7$
Sol :
$14.49 \div 7$ $=\dfrac{1449}{100} \div 7 $ $=\dfrac{1449}{100} \times \dfrac{1}{7}$ $=\dfrac{207}{100}$ = 2.07

(vii) $3.96 \div 4$
Sol :
$3.96 \div 4$ $=\dfrac{396}{100} \div 4$  $=\dfrac{396}{100} \times \dfrac{1}{4}$ $=\dfrac{99}{100}$ = 0.99

(viii) $0.80 \div 5$
Sol :
$0.80 \div 5$ $=\dfrac{80}{100} \div 5$ $=\dfrac{80}{100} \times \dfrac{1}{5}$ $=\dfrac{16}{100}$ =0.16


Q 2, Ex 2.7 - Fractions and Decimals - Chapter 2 - Maths Class 7th - NCERT



Question 2
Find:
(i) $4.8 \div  10$
Sol : 0.48

(ii) $52.5 \div 10$
Sol : 5.25

(iii) $0.7 \div  10$
Sol : 0.07

(iv) $33.1 \div 10$
Sol : 3.31

(v) $272.23 \div 10$
Sol : 27.223

(vi) $0.56 \div 10$
Sol : 0.056

(vii) $397\div 10$
Sol : 0.397

Note : We know that when a decimal number is divided by a multiple of 10 only (i.e., 10, 100, 1000, etc.), the decimal point will be shifted to the left by as many places as there are zeroes. Since here we are dividing by 10, the decimal will shift to the left by 1 place.


Q 3, Ex 2.7 - Fractions and Decimals - Chapter 2 - Maths Class 7th - NCERT



Question 3
Find:
(i) $2.7 \div 100$
Sol : 0.027

(ii) $0.3 \div 100$
Sol : 0.003

(iii) $0.78 \div 100$
Sol : 0.0078

(iv) $432.6 \div 100$
Sol : 4.326

(v) $23.6 \div 100$
Sol : 0.236

(vi) $98.53 \div 100$
Sol : 0.9853

Notes : We know that when a decimal number is divided by a multiple of 10 only (i.e., 10, 100, 1000, etc.), the decimal point will be shifted to the left by as many places as there are zeroes. Since here we are dividing by 100, the decimal will shift to the left by 2 places.


Q 4, Ex 2.7 - Fractions and Decimals - Chapter 2 - Maths Class 7th - NCERT


Question 4
Find:
(i) $7.9 \div 1000$
Sol : 0.0079

(ii) $26.3 \div 1000$
Sol : 0.0263

(iii) $38.53 \div 1000$
Sol : 0.03853

(iv) $128.9 \div 1000$
Sol : 0.1289

(v) $0.5 \div 1000$
Sol : 0.0005


Q 5, Ex 2.7 - Fractions and Decimals - Chapter 2 - Maths Class 7th - NCERT



Question 5
Find:
(i) $7 \div 3.5$
Sol :
$7 \div 3.5$ $=7 \div \dfrac{35}{10}$ $=35 \times \dfrac{10}{35}$  = 2

(ii) $36 \div 0.2$
Sol :
$36 \div 0.2$ $=36 \div \dfrac{2}{10}$ $=36 \times \dfrac{10}{2}$  = 180

(iii) $3.25 \div 0.5$
Sol :
$3.25 \div 0.5$ $=\dfrac{325}{100} \div \dfrac{5}{10}$ $=\dfrac{325}{100} \times \dfrac{10}{5}$ $=\dfrac{65}{10}$ = 6.5

(iv) $30.94\div 0.7$
Sol :
$30.94\div 0.7$ $=\dfrac{3094}{100} \div \dfrac{7}{10}$ $=\dfrac{3094}{100} \times \dfrac{7}{10}$ $=\dfrac{442}{10}$ = 44.2

(v) $0.5 \div 0.25$
Sol :
$0.5 \div 0.25$ $=\dfrac{5}{10} \div \dfrac{25}{100}$ $=\dfrac{5}{10} \times \dfrac{100}{25}$  = 2

(vi) $7.75 \div 0.25$
Sol :
$7.75 \div 0.25$ $=\dfrac{775}{100} \div \dfrac{25}{100}$ $=\dfrac{775}{100} \times \dfrac{100}{25}$  = 31

(vii) $76.5 \div 0.15$
Sol :
$76.5 \div 0.15$ $=\dfrac{765}{10} \div \dfrac{15}{100}$ $=\dfrac{765}{10} \times \dfrac{100}{15}$ = 510

(viii) $37.8 \div 1.4$
Sol :
$37.8 \div 1.4$ $=\dfrac{378}{10} \div \dfrac{14}{10}$ $=\dfrac{378}{10} \times \dfrac{10}{14}$  = 27

(ix) $2.73 \div 1.3$
Sol :
$2.73 \div 1.3$ $=\dfrac{273}{100} \div \dfrac{13}{10}$ $=\dfrac{273}{100} \times \dfrac{10}{13}$ $=\dfrac{21}{10}$ = 2.1


Q 6, Ex 2.7 - Fractions and Decimals - Chapter 2 - Maths Class 7th - NCERT



Question 6
A vehicle covers a distance of 43.2 km in 2.4 litres of petrol. How much distance will it cover in one litre of petrol?
Sol :
Distance covered in 2.4 litres of petrol = 43.2 km
$\therefore$ Distance covered in 1 litre of petrol $=43.2\div 2.4$ $=\dfrac{432}{10} \div \dfrac{24}{10}$ $=\dfrac{432}{10} \div \dfrac{10}{24}$ = 18
Therefore, the vehicle will cover 18 km in 1 litre petrol.

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