EXERCISE 10.5
Q 1, Ex 10.5 - Practical Geometry - Chapter 10 - Maths Class 7th - NCERT
Page No 203:
Question 1:
Construct the right angled ΔPQR, where m∠Q = 90°, QR = 8 cm and PR = 10 cm.Answer:
A rough sketch of ΔPQR is as follows.
The steps of construction are as follows.
(i) Draw a line segment QR of length 8 cm.
(ii) At point Q, draw a ray QX making 90º with QR.
(iii) Taking R as centre, draw an arc of 10 cm radius to intersect ray QX at point P.
(iv) Join P to R. ΔPQR is the required right-angled triangle.
Q 2, Ex 10.5 - Practical Geometry - Chapter 10 - Maths Class 7th - NCERT
Question 2:
Construct a right-angled triangle whose hypotenuse is 6 cm long and one of the legs is 4 cm long.Answer:
A right-angled triangle ABC with hypotenuse 6 cm and one of the legs as 4 cm has to be constructed. A rough sketch of ΔABC is as follows.
The steps of construction are as follows.
(i) Draw a line segment BC of length 4 cm.
(ii) At point B, draw a ray BX making an angle of 90º with BC.
(iii) Taking C as centre, draw an arc of 6 cm radius to intersect ray BX at point A.
(iv) Join A to C to obtain the required ΔABC.
Q 3, Ex 10.5 - Practical Geometry - Chapter 10 - Maths Class 7th - NCERT
Question 3:
Construct an isosceles right-angled triangle ABC, where, m∠ACB = 90° and AC = 6 cm.Answer:
In an isosceles triangle, the lengths of any two sides are equal.Let in ΔABC, AC = BC = 6 cm. A rough sketch of this ΔABC is as follows.
The steps of construction are as follows.
(i) Draw a line segment AC of length 6 cm.
(ii) At point C, draw a ray CX making an angle of 90º with AC.
(iii) Taking point C as centre, draw an arc of 6 cm radius to intersect CX at point B.
(iv) Join A to B to obtain the required ΔABC.
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