EXERCISE 3.3
Q 1(ii), Ex 3.3 - Linear Equations - Chapter 3 - Maths Class 10th - NCERT
Q 1(iv), Ex 3.3 - Linear Equations - Chapter 3 - Maths Class 10th - NCERT
Page No 53:
Question 1:
Solve the following pair of linear equations by the substitution method.
Answer:
(i) x + y = 14 (1)x − y = 4 (2)
From (1), we obtain
x = 14 − y (3)
Substituting this value in equation (2), we obtain
Substituting this in equation (3), we obtain
(ii)
From (1), we obtain
Substituting this value in equation (2), we obtain
Substituting in equation (3), we obtain
s = 9
s = 9, t = 6(iii)3x − y = 3 (1)
9x − 3y = 9 (2)
From (1), we obtain
y = 3x − 3 (3)
Substituting this value in equation (2), we obtain
9 = 9
This is always true.
Hence, the given pair of equations has infinite possible solutions and the relation between these variables can be given by
y = 3x − 3
Therefore, one of its possible solutions is x = 1, y = 0.
(iv)
From equation (1), we obtain
Substituting this value in equation (2), we obtain
Substituting this value in equation (3), we obtain
(v)
From equation (1), we obtain
Substituting this value in equation (2), we obtain
Substituting this value in equation (3), we obtain
x = 0
x = 0, y = 0(vi)
From equation (1), we obtain
Substituting this value in equation (2), we obtain
Substituting this value in equation (3), we obtain
Hence, x = 2, y = 3
Q 2, Ex 3.3 - Linear Equations - Chapter 3 - Maths Class 10th - NCERT
Question 2:
Solve 2x + 3y = 11 and 2x − 4y = − 24 and hence find the value of ‘m’ for which y = mx + 3.Answer:
From equation (1), we obtain
Substituting this value in equation (2), we obtain
Putting this value in equation (3), we obtain
Hence, x = −2, y = 5
Also,
Q 3(i), Ex 3.3 - Linear Equations - Chapter 3 - Maths Class 10th - NCERT
Q 3(ii), Ex 3.3 - Linear Equations - Chapter 3 - Maths Class 10th - NCERT
Q 3(iii), Ex 3.3 - Linear Equations - Chapter 3 - Maths Class 10th - NCERT
Q 3(iv), Ex 3.3 - Linear Equations - Chapter 3 - Maths Class 10th - NCERT
Q 3(v), Ex 3.3 - Linear Equations - Chapter 3 - Maths Class 10th - NCERT
Question 3:
Answer:
(i) Let the first number be x and the other number be y such that y > x.According to the given information,
On substituting the value of y from equation (1) into equation (2), we obtain
Substituting this in equation (1), we obtain
y = 39
Hence, the numbers are 13 and 39.
(ii) Let the larger angle be x and smaller angle be y.
We know that the sum of the measures of angles of a supplementary pair is always 180º.
According to the given information,
From (1), we obtain
x = 180º − y (3)
Substituting this in equation (2), we obtain
Putting this in equation (3), we obtain
x = 180º − 81º
= 99º
Hence, the angles are 99º and 81º.
(iii) Let the cost of a bat and a ball be x and y respectively.
According to the given information,
From (1), we obtain
Substituting this value in equation (2), we obtain
Substituting this in equation (3), we obtain
Hence, the cost of a bat is Rs 500 and that of a ball is Rs 50.
(iv) Let the fixed charge be Rs x and per km charge be Rs y.
According to the given information,
From (1), we obtain
Substituting this in equation (2), we obtain
Putting this in equation (3), we obtain
Hence, fixed charge = Rs 5
And per km charge = Rs 10
Charge for 25 km = x + 25y
= 5 + 250 = Rs 255
(v) Let the fraction be
.According to the given information,
From equation (1), we obtain
Substituting this in equation (2), we obtain
Substituting this in equation (3), we obtain
Hence, the fraction is
.(vi) Let the age of Jacob be x and the age of his son be y.
According to the given information,
From (1), we obtain
Substituting this value in equation (2), we obtain
Substituting this value in equation (3), we obtain
Hence, the present age of Jacob is 40 years whereas the present age of his son is 10 years.
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