EXERCISE 2.4
Q 1 (i), Ex 2.4 - Polynomials - Chapter 2 - Maths Class 10th - NCERT
Q 1 (ii), Ex 2.4 - Polynomials - Chapter 2 - Maths Class 10th - NCERT
Question 1:
Verify that the numbers given alongside of the cubic polynomials below are their zeroes. Also verify the relationship between the zeroes and the coefficients in each case:
Answer:
(i)


Therefore,

Comparing the given polynomial with


Therefore, the relationship between the zeroes and the coefficients is verified.
(ii)



Therefore, 2, 1, 1 are the zeroes of the given polynomial.
Comparing the given polynomial with

Verification of the relationship between zeroes and coefficient of the given polynomial

Multiplication of zeroes taking two at a time = (2)(1) + (1)(1) + (2)(1) =2 + 1 + 2 = 5

Multiplication of zeroes = 2 × 1 × 1 = 2

Hence, the relationship between the zeroes and the coefficients is verified.
Q 2, Ex 2.4 - Polynomials - Chapter 2 - Maths Class 10th - NCERT
Question 2:
Find a cubic polynomial with the sum, sum of the product of its zeroes taken two at a time, and the product of its zeroes as 2, − 7, − 14 respectively.Answer:
Let the polynomial be

It is given that

If a = 1, then b = −2, c = −7, d = 14
Hence, the polynomial is

Q 3, Ex 2.4 - Polynomials - Chapter 2 - Maths Class 10th - NCERT
Page No 37:
Question 3:
If the zeroes of polynomial

Answer:

Zeroes are a − b, a + a + b
Comparing the given polynomial with

p = 1, q = −3, r = 1, t = 1

The zeroes are


Hence, a = 1 and b =


Q 4, Ex 2.4 - Polynomials - Chapter 2 - Maths Class 10th - NCERT
Question 4:
]It two zeroes of the polynomial

Answer:
Given that 2 +


Therefore,

= x2 − 4x + 1 is a factor of the given polynomial
For finding the remaining zeroes of the given polynomial, we will find the quotient by dividing


Clearly,


It can be observed that

And


Therefore, the value of the polynomial is also zero when


Or x = 7 or −5
Hence, 7 and −5 are also zeroes of this polynomial.
Q 5, Ex 2.4 - Polynomials - Chapter 2 - Maths Class 10th - NCERT
Question 5:
If the polynomial

Answer:
By division algorithm,Dividend = Divisor × Quotient + Remainder
Dividend − Remainder = Divisor × Quotient


Let us divide



It can be observed that

Therefore,


For

2 k =10
And thus, k = 5
For

10 − a − 8 × 5 + 25 = 0
10 − a − 40 + 25 = 0
− 5 − a = 0
Therefore, a = −5
Hence, k = 5 and a = −5
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