EXERCISE 2.4
Q 1 (i), Ex 2.4 - Polynomials - Chapter 2 - Maths Class 10th - NCERT
Q 1 (ii), Ex 2.4 - Polynomials - Chapter 2 - Maths Class 10th - NCERT
Question 1:
Verify that the numbers given alongside of the cubic polynomials below are their zeroes. Also verify the relationship between the zeroes and the coefficients in each case:
Answer:
(i)
Therefore,
Comparing the given polynomial with

Therefore, the relationship between the zeroes and the coefficients is verified.
(ii)

Therefore, 2, 1, 1 are the zeroes of the given polynomial.
Comparing the given polynomial with
Verification of the relationship between zeroes and coefficient of the given polynomial
Multiplication of zeroes taking two at a time = (2)(1) + (1)(1) + (2)(1) =2 + 1 + 2 = 5
Multiplication of zeroes = 2 × 1 × 1 = 2
Hence, the relationship between the zeroes and the coefficients is verified.
Q 2, Ex 2.4 - Polynomials - Chapter 2 - Maths Class 10th - NCERT
Question 2:
Find a cubic polynomial with the sum, sum of the product of its zeroes taken two at a time, and the product of its zeroes as 2, − 7, − 14 respectively.Answer:
Let the polynomial beIt is given that

If a = 1, then b = −2, c = −7, d = 14
Hence, the polynomial is
Q 3, Ex 2.4 - Polynomials - Chapter 2 - Maths Class 10th - NCERT
Page No 37:
Question 3:
If the zeroes of polynomialAnswer:
Zeroes are a − b, a + a + b
Comparing the given polynomial with
p = 1, q = −3, r = 1, t = 1

The zeroes are

Hence, a = 1 and b =
Q 4, Ex 2.4 - Polynomials - Chapter 2 - Maths Class 10th - NCERT
Question 4:
]It two zeroes of the polynomialAnswer:
Given that 2 +Therefore,
= x2 − 4x + 1 is a factor of the given polynomial
For finding the remaining zeroes of the given polynomial, we will find the quotient by dividing

Clearly,
It can be observed that
And
Therefore, the value of the polynomial is also zero when
Or x = 7 or −5
Hence, 7 and −5 are also zeroes of this polynomial.
Q 5, Ex 2.4 - Polynomials - Chapter 2 - Maths Class 10th - NCERT
Question 5:
If the polynomialAnswer:
By division algorithm,Dividend = Divisor × Quotient + Remainder
Dividend − Remainder = Divisor × Quotient
Let us divide

It can be observed that
Therefore,
For
2 k =10
And thus, k = 5
For
10 − a − 8 × 5 + 25 = 0
10 − a − 40 + 25 = 0
− 5 − a = 0
Therefore, a = −5
Hence, k = 5 and a = −5
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